The expected value is sum of n*P(n), for all possible values of n.
0*0.84 + 1*0.13 + 2*0.02 + 3*0.01
= 0.20
The number of accidents that occur at the intersection of Pine and Linden streets between 3 pm. and 6 pm. on Friday afternoons is 0,1,2, or 3, with probabilities of 0.84, 0.13. 0.02, and 0.01. What is the expected value for the random variable given the number of accidents?
1 answer