The normal boiling point of liquid ethanol is 351 K. Assuming that its molar heat of vaporization is constant at 37.5 kJ/mol, the boiling point of C2H5OH when the external pressure is 1.35 atm is K.

Question

The normal boiling point of liquid ethanol is 351 K. Assuming that its molar heat of vaporization is constant at 37.5 kJ/mol, the boiling point of C2H5OH when the external pressure is 1.35 atm is     K.

DrBob222 · Answer

Use the Clausius-Clapeyron equation. You know p = 1 atm when T = 351K. Solve for p2 when T = 1.35 atm.