Asked by Jessica
At a pressure of 1ATM, _____ KJ of heat is needed to vaporize a 32.3 g sample of liquid ethanol at its normal boiling point of 78.4 C. Boiling point (78.4 C), specific heat (2.46 J/g C), and Hvap(78.4 C)=38.6 KJ/mol are provided. Please include how to solve step by step so I can understand for similar problems. Thanks
Answers
Answered by
Scott
find the number of moles in 32.3 g
... the molar mass is 46.1 g
multiply by the heat of vaporization (Hvap)
... the molar mass is 46.1 g
multiply by the heat of vaporization (Hvap)
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