The near and the far points of a short-sighted are 8 cm and 20 cm from the eyeball.

a) What power of corrective lens is needed for this eye to see distant objects clearly?
b)What will the resulting near point then be?(Assume that the lens is placed very close to the eye)

Answers so far:
a) 1/f = 1/u + 1/v
1/f = 1/0.08 + 1/0.20
1/f = 17.5
P = 1/f
P = 17.5 D

b) 1/∞ + 1/-0.2 = 1/f
f = 0

Similar Questions
  1. Choose the answer that best matches the word in italics.Eckels was not killed for being craven but because of his impact on the
    1. answers icon 1 answer
  2. Choose the answer that best matches the word in italics.Eckels was not killed for being *craven* but because of his impact on
    1. answers icon 1 answer
  3. Choose the answer that best matches the word in italics.Eckels was not killed for being craven but because of his impact on the
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions