In y
max height:
y = v^2/g
time:
t = 2v/g
In x
x = vt (you found from y)
The muzzle velocity of a projectile fired from a gun has an upward component of 49 m/s and a horizontal component of 60 m/s.
A. What Maximum height does the projectile reach?
B. How far forward does it go (assume a level surface)
Show step by step and how you did it and explain.
1 answer
1 answer