The molar heat of fusion for water is 6.01 kJ/mol. How much energy must be added to a 75.0-g block of ice at 0°C to change it to 75.0 g of liquid water at 0°C?

Question

1.44 kJ
10.18 kJ
12.48 kJ
25.04 kJ

Answer 1

q = mass x heat fusion = ?
q = 75 g x (1 mol H2O/18 g) x 6.02 = ? kJ.

Answer 2

45

Answer 3

12.48