How much energy (in kilojoules) is needed to heat 5.55g of ice from -13.5 ∘ C to 26.5 ∘ C. The heat of fusion of water is 6.01kJ/mol, and the molar heat capacity is 36.6 J/(K⋅mol) for ice and 75.3 J/(K⋅mol) for liquid water.

Answer 1

So this in steps.
Within a phase the formula is
q = mass x specific heat x (Tfinal-Tinitial).
For example, to heat liquid H2O from zero C to 100 C use
q = mass x specific heat x (100-0) = ?

At a phase change (from ice to liquid at the melting point or from liquid to steam at 100 c), use
q = mass x heat fusion (at melting point) or
q = mass x heat vaporization (at boiling point)
Then add each q to find the sum.