The molar enthalpy of vaporization for water

Question

is 40.79 kJ/mol. Express this enthalpy of
vaporization in joules per gram.
b. The molar enthalpy of fusion for water is
6.009 kJ/mol. Express this enthalpy of fusion
in joules per gram.

Answer 1

40.79 kJ/mol x (1000 J/kJ) x (1 mol H2O/18.015 g H2O) = ?

You do b in a similar fashion. It's simply a matter of making the dimensional factors work for you.

Answer 2

73.50 j/gram