The molar enthalpy of vaporization for water is 40.79 kJ/mol. Express this enthalpy of vaporization in joules per gram.

2 answers

40.79 kJ/mol x (1000 J/kJ) x (1 mol/18 g) = ?
2266J/g
Similar Questions
  1. The molar enthalpy of vaporization for wateris 40.79 kJ/mol. Express this enthalpy of vaporization in joules per gram. b. The
    1. answers icon 1 answer
  2. The molar enthalpy of vaporization for wateris 40.79 kJ/mol. Express this enthalpy of vaporization in joules per gram. b. The
    1. answers icon 2 answers
  3. i have one more question:I know this one has to do with hess's law but i'm not sure of how to get the enthalpy of vaporization
    1. answers icon 2 answers
    1. answers icon 2 answers
more similar questions