To find the mass of Fe produced from 10g of iron(III) oxide, we first need to determine the molar mass of Fe2O3 and Fe.
Fe2O3:
Fe = 55.85 g/mol
O = 16.00 g/mol
Total molar mass = 2(55.85) + 3(16.00) = 159.70 g/mol.
Now, to calculate the number of moles of Fe2O3 in 10g:
Number of moles = Mass / Molar mass
Number of moles = 10g / 159.70 g/mol = 0.0627 mol
From the balanced equation, it shows that 1 mole of Fe2O3 produces 2 moles of Fe.
Therefore, the number of moles of Fe produced from 0.0627 moles of Fe2O3 would be:
Number of moles of Fe = 0.0627 mol * (2 moles Fe / 1 mole Fe2O3) = 0.1254 mol.
Next, calculate the mass of Fe produced:
Mass of Fe = Number of moles * Molar mass
Mass of Fe = 0.1254 mol * 55.85 g/mol = 7.01 g.
Therefore, the mass of Fe produced from 10g of iron(III) oxide is 7.01 grams.
The mass of Fe produced from 10g of iron(111) oxide as shown from the balanced equation Fe2O3 + 3CO = 2Fe + 3CO2
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