The equation you wrote is not correct. It should be Al2O3(s). Also, I don't know how you make FeO and Al2O3 in aqueous solutions.
2Al + 3FeO → 3Fe + Al2O3
mols Al = g/atomic mass = 94.7g/27 = 3.51. Convert to mols Fe this way.
3.51 mols Al x (3 mols Fe/2 mol Al) = 5.26 mols Fe produced.
Convert to g Fe this way. grams Fe = mols Fe x atomic mass Fe = ?
Given the following balanced equation, determine the mass of iron metal that would be produced from the complete reaction of 94.7g of aluminum with excess iron II oxide.
2 Al(s) + 3FeO(aq) → 3Fe(s) + Al2O(aq)
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