The man fires an 75g arrow so that it is moving at 80 m/s when it hits and embeds in a 13kg block resting on ice. What is the velocity of the block and arrow just after the collision? How far will the block slide on the ice before stopping? A 7.2N friction force opposes its motion.

Answer 1

M!*V1 + M2*V2 = M1*V + M2*V
0.075*80 + 13*0 = 0.075*V + 13*V
6 + 0 = 13.075V

Answer 2

Momentum before the collision=Momentum
after the collision:
M1*V1 + M2*V2 = M1*V + M2*V
0.075*80 + 13*0 = 0.075*V + 13*V
6 + 0 = 13.075V
V = 0.459 m/s