Two radii of the circle are the lines perpendicular to the given lines. They are
y = -3/2 (x-3)+4
y = 3/2 (x-3)+10
They intersect at the center of the circle: (1,7)
The radius of the circle is r^2 = (1-3)^2 + (7-4)^2 = 13
The circle is (x-1)^2 + (y-7)^2 = 13
The lines y=(2/3)x+2 and y=(-2/3)x+12 are tangent to circle C at the points (3,4) and (3,10), respectively.
a) Find the coordinates of C and the radius of circle C. Explain your reasoning.
b)Write the standard equation of circle C.
3 answers
Thanks for your response oobleck!
When finding radii equations, why did you say "(x-3)?"
When finding radii equations, why did you say "(x-3)?"
review the point-slope form of a line.
the line with slope m through (h,k) is
y-k = m(x-h)
the line with slope m through (h,k) is
y-k = m(x-h)