The length of a spring when a mass of 20g is hung from its end is 14cm,while its total length is 16cm when a mass of 30g is hung from the same end.calculate the unstretched spring assuming Hooke's law is obeyed.

Answer 1

k = (M2-M1)/(L2-L1) = (30-20)/(16-14) = 5 g/cm.

d = 20g * 1cm/5g = 4cm = Distance stretched.

Lu = 14-4 = 10cm = Un-stretched length.

Answer 2

Well we are all learning, but I personally don't understand how you get that Distance Stretched and the Unstreched Lenght please........
If you can do so I will be so grateful.

Answer 3

For the second step F= ke
Therefore, e=F/k = 20/5 =4cm
For the unstreched length (original length) = L1 - e = 14 - 4 = 10cm

Answer 4

Ope I want to understand how u got that 5 that you said 20/5. How did u get it 🤕😵

Answer 5

I understand the unstretch3d length but where did u get 1 feom

Answer 6

I understand the unstretch3d length but where did u get 1 from