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The length of a rectangular piece of property is 1 foot more that twice the width if the perimeter is 302 feet, find the length and width

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w = width
2w + 1 = length
P = 2w + 2L

302 = 2w + 2(2w + 1)
Solve for w, the width.
length = 2w + 1

50 feet

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