w = width
2w + 1 = length
P = 2w + 2L
302 = 2w + 2(2w + 1)
Solve for w, the width.
length = 2w + 1
The length of a rectangular piece of property if 1 foot more than twice the width. If the perimeter is 302 feet, find the length and width.
2 answers
43