length is L = W + 8
Area is length times width.
560 = (w+8)w
560 = w^2 + 8w
0 = w^2 + 8w - 560
factor to solve for w. (discard negative values) Then substitute to find L.
Be sure to check by multiplying to be sure you get the 560 in^2.
the length of a rectangular photograph is 8in. more than the width. if the area is 560 in^2 what are the dimensions of the photograph?
the width is____ in. and the length is ____ in.
1 answer