The length of a rectangular field is 7 meters more than twice its width. If the perimeter is 140 meters, find the dimensions of the field.
7 answers
31.5 and 38.5
Oh wait, I read it wrong, sorry.
width --- x
length -- x+7
2(x + x+7) = 140
easy to solve...
length -- x+7
2(x + x+7) = 140
easy to solve...
and I read it wrong as well, lol
width --- x
length -- 2x+7
2(x + 2x+7) = 140
easy to solve...
width --- x
length -- 2x+7
2(x + 2x+7) = 140
easy to solve...
P=2(l+w)
width=w
length=2w+7
(w)+(w)+(2w+7)+(2w+7)=140
6w+14=140
6w=140-14
6w=126
w=126/6
w=21(width)
l=2w+7
2*21=42+7=49 (length)
width=w
length=2w+7
(w)+(w)+(2w+7)+(2w+7)=140
6w+14=140
6w=140-14
6w=126
w=126/6
w=21(width)
l=2w+7
2*21=42+7=49 (length)
I am 100% sure that my answer is right!!
By the way,in what grade is the person who asked this question (just wondering...)
By the way,in what grade is the person who asked this question (just wondering...)
width= x
lengtth=x+2
so
x(x+2)=170
easy to solve....................
lengtth=x+2
so
x(x+2)=170
easy to solve....................