A rectangular field is 90 meters long and 60 meters wide. Give the length and width of another rectangular field that has the same perimeter but a smaller area.

Answer 1

The perimeter of the first rectangular field is equal to:

2(length + width) = 2(90 + 60) = 2(150) = 300 meters

To find the dimensions of another rectangular field with the same perimeter but a smaller area, we need to divide the perimeter by 2 and subtract the length and width of the first rectangular field.

300 / 2 = 150

Let's assume the length of the second rectangular field is x and the width is y.

Therefore, x + y = 150

To find the dimensions of the second rectangular field with the smallest area, we need to consider the other information given. The length of the first rectangular field is 90 meters, so the length of the second rectangular field should be smaller than 90 meters.

Let's assign x = 89.

Now, we can find the value of y.

x + y = 150
89 + y = 150
y = 150 - 89
y = 61

Therefore, the length of the second rectangular field is 89 meters and the width is 61 meters.