Let W = width
L = 2W +50
2L + 2W = 700
Substitute 2W + 50 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.
The length of a rectangular field is 50 meters more than twice its width. If the perimeter is 700 meters, find the dimensions of the field.
1 answer
1 answer