P = 2L + 2W
58 = 2(W + 3) + 2W
Solve for W.
The length of a rectangle is 3 more than it's width. the perimeter of the rectangle is 58cm. what are the rectangle dimensions?
2 answers
w and w+3
perimeter = 2 w + 2 (w +3) = 58
4 w + 6 = 58
4 w = 52
w = 13
so 13 by 16
perimeter = 2 w + 2 (w +3) = 58
4 w + 6 = 58
4 w = 52
w = 13
so 13 by 16
6 answers