The length of a rectangle exceeds twice its width by 4 feet.

If the area of the rectangle is 286 square feet, find the dimensions.

1 answer

width --- x
length --- 2x+4

x(2x+4) = 286
2x^2 + 4x - 286 = 0
x^2 + 2x - 143 = 0
(x+13)(x-11) = 0
x = 11 or x = -13, the last part is not possible

the width is 11, the length is 26

check:
26 is 4 more than twice 11
area = 11(26) = 286