Asked by shehzad
the lenght of a rectangle exceeds its width by 7 m. if the width is decreased by 3m and the length decreasesd by 10 m the area is decreased by 95 sq. metres find the dimensions of the rectangle.
Answers
Answered by
Reiny
now:
width --- x
length -- x+7
after change:
width = x-3
length = x+7 - 10 = x-3
(notice the new rectangle is now a square)
original area = x(x+7)
new area = (x-3)(x-3)
the difference is 95 , so ....
x(x+7) - (x-3)^2 = 95
x^2 + 7x - (x^2 - 6x + 9) = 95
carry on, it is easy
width --- x
length -- x+7
after change:
width = x-3
length = x+7 - 10 = x-3
(notice the new rectangle is now a square)
original area = x(x+7)
new area = (x-3)(x-3)
the difference is 95 , so ....
x(x+7) - (x-3)^2 = 95
x^2 + 7x - (x^2 - 6x + 9) = 95
carry on, it is easy
Answered by
Selvam M
Width = 8 m
Length= 15 m
Area = 120 sq m
Length= 15 m
Area = 120 sq m
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