the legth of a side of a square is represented by (3x-1). if the perimeter of the square is 68, find t

he value of x

4 answers

4(3x-1) = 68

continue ....
perimeter of the square = 4a
a is the side of square
3x-1=68
solve the equ u get the ans :)
4(3x - 1) = 68

12x - 4 = 68

12x = 72

x = ?
sorry reiny is right 4(3x-1)=68