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the integral part of the logarithms of 0.00068 is ................?Asked by Precious
The Integral part of the logarithms of 0.00068
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Answered by
mathhelper
In the good ol' days (before calculators)
.00068
= 6.8 * 10^-4
log .00068
= log (6.8 * 10^-4)
= log 6.8 + log 10^-4
= .8325 - 4
so the inegral part of log .00068, also called the characteristic , is -4
The decimal part is called the mantissa, and is always positive.
in 2022, enter log .00068 on your calculator to get -3.1675 , rounded to 4 decimals
it would be incorrect to say that the integral part is -3, it is -4
notice that .8325 - 4 = -3.1675
(are you using tables to do log calculations ??)
.00068
= 6.8 * 10^-4
log .00068
= log (6.8 * 10^-4)
= log 6.8 + log 10^-4
= .8325 - 4
so the inegral part of log .00068, also called the characteristic , is -4
The decimal part is called the mantissa, and is always positive.
in 2022, enter log .00068 on your calculator to get -3.1675 , rounded to 4 decimals
it would be incorrect to say that the integral part is -3, it is -4
notice that .8325 - 4 = -3.1675
(are you using tables to do log calculations ??)
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