First of all, you have to write the equation. Call the shorter leg of the triangle x.
x^2 + (x+2)^2 = 10^2 = 100
2x^2 + 4x + 4 = 100
x^2 + 2x -48 = 0
(x+8)(x-6) = 0
Solve for x etc
The hypotenuse of a right triangle measures 10m. One leg of the triangle is 2m longer then the other. Find the lengths of the legs.
How would you solve this equation?
2 answers
thank you :)
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