The Hubble Space Telescope orbits Earth 621 km above Earth's surface. What is the period of the telescope's orbit? Give answer with 5 significant figures.

Answer 1

The period is given by

T = 2 * pi * (r^3/(G*M))^0.5

where T is the period, r is the radius, G is the gravitational constant, M is the mass of the earth

convert 621 km to meters
look up the Gravitational constant and the mass of the earth in kg

plug in the numbers, and solve