Asked by stacy
The higher the energy level occupied by an electron in the hydrogen atom, the larger the atom. The diameter of the atom is proportional to n2, where n = 1 labels the lowest, or "ground" state, n = 2 is the second state, n = 3 is the third state, and so on. If the atom's diameter is 1 multiplied by 10-10 m in its lowest energy state, what is its diameter in state number 52? 1 m How many unexcited atoms could be fit within this one giant atom?
Answers
Answered by
drwls
<<If the atom's diameter is 1 multiplied by 10^-10 m in its lowest energy state, what is its diameter in state number n = 52? >>
52^2 times higher than the n = 1 diameter
<< How many unexcited atoms could be fit within this one giant atom?>>
[52^2]^3 = 52^6 = ____
52^2 times higher than the n = 1 diameter
<< How many unexcited atoms could be fit within this one giant atom?>>
[52^2]^3 = 52^6 = ____
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