Asked by Will
                The higher the energy level occupied by an electron in the hydrogen atom, the larger the atom.  The diameter of the atom is proportional to n2, where n=1 labels the lowest, or “ground” state, n=3 is the third state, and so on.  If the atom’s diameter is 1x10-10m in its lowest energy state, what is its diameter in state number 50?  How many unexcited atoms could be fit within this one giant atom?
            
            
        Answers
                    Answered by
            bobpursley
            
    diameter=1E-10*50^2 according to the problem statement.
numberunexcited=volumeexcited/volumeunexcited.
V=4/3 PI radius^3
    
numberunexcited=volumeexcited/volumeunexcited.
V=4/3 PI radius^3
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