The height of an equilateral triangle equals the square root of 3 over 2 times the side length. Using 7/4 for the square root of 3, what is the approximate height in meters of an equilateral triangle with a side of 8 meters?

Answer 1

To find the height of an equilateral triangle, you can multiply the side length by the expression $\dfrac{\sqrt{3}}{2}$.

Given that $\sqrt{3} \approx \dfrac{7}{4}$ and the side length is 8 meters, we can substitute these values into the expression:

Height $= 8 \times \dfrac{7}{4} = \dfrac{56}{4} = 14$ meters.

Therefore, the approximate height of the equilateral triangle is 14 meters.