The height of an equilateral triangle equals Square 3/2 times the side of length using 7/4 for the square root of 3 what is the approximate height in meters of the equilateral triangle with the side length of 8 m

Answer 1

To find the height of an equilateral triangle, you can use the formula:

\[ \text{Height} = \frac{\sqrt{3}}{2} \times \text{side length} \]

Given that the side length is 8 meters and using the approximation for \(\sqrt{3}\) as \( \frac{7}{4} \):

\[ \text{Height} = \frac{\frac{7}{4}}{2} \times 8 \]

First, calculate \(\frac{\frac{7}{4}}{2}\):

\[ \frac{7}{4} \div 2 = \frac{7}{4} \times \frac{1}{2} = \frac{7}{8} \]

Now, substitute this back into the height formula:

\[ \text{Height} = \frac{7}{8} \times 8 \]

Now simplifying the equation:

\[ \text{Height} = 7 \text{ meters} \]

Therefore, the approximate height of the equilateral triangle with a side length of 8 meters is 7 meters.