The height of a projectile fired upward is given by the formula s = v0t – 16t^2, where s is the height, v0 is the initial velocity and t is the time. Find the times at which a projectile with an initial velocity of 128 ft/s will be 176 ft above the ground. Round to the nearest hundredth of a second.

1 answer

so your equation would clearly be
s = 128t - 16t^2
you want that to be 176

176 = 128t - 16t^2
16t^2 - 128t + 176 = 0
all 3 terms divide by 16, how nice
t^2 - 8t + 11 = 0

Use your favourite method to solve this.
You will get 2 positive answers, explained by the fact that the height will be
176 ft on its way up (the smaller t value) and 176 ft on its way down (the larger t)