so you are solving
96 = 128 - 16t^2
16t^2 = 32
t = √2
I will leave the rounding to you.
The height of a projectile fired upward is given by the formula
s = v0t − 16t2,
where s is the height in feet,
v0
is the initial velocity, and t is the time in seconds. Find the time for a projectile to reach a height of 96 ft if it has an initial velocity of 128 ft/s. Round to the nearest hundredth of a second.
2 answers
should have been
96 = 128t - 16t^2
16t^2 - 128t + 96 = 0
t^2 - 8t + 6 = 0
t = 4 + √10 or 4 - √10
There are two possible answers, since the height of 96 feet is reached on its upwards flight, and then again when it comes back down.
96 = 128t - 16t^2
16t^2 - 128t + 96 = 0
t^2 - 8t + 6 = 0
t = 4 + √10 or 4 - √10
There are two possible answers, since the height of 96 feet is reached on its upwards flight, and then again when it comes back down.