0 at ground = - 16 t^2 + 784
so
t^2 = 784
t = sqrt (784)
The height, in feet, of a free�]falling object t seconds after being dropped from an initial height s can be found using the function h = �]16t2 + s. An object is dropped from a helicopter 784 feet above the ground. How long will it take the object to land on the ground?
3 answers
0 at ground = - 16 t^2 + 784
so
t^2 = 784 / 16
t = sqrt (784 / 16)
so
t^2 = 784 / 16
t = sqrt (784 / 16)
49