the heat of neutralization for a strong acid in dilute water solution is about 60 kJ/mol of H+. What quantity of heat in kJ is produced when 100 mL of 3 M HCl is mixed with 100 mL of 1 M KOH?

Answer 1

0.100 L x 3 M HCl = 0.3 mol HCl
0.100 L x 1 M KOH = 0.1 mol KOH.
So it looks like 0.1 mole will be neutralized and it is 60 kJ/mol so
0.1 x 60 = ??