UPDATE: is this correct?
c = Q/mΔT
330000 = Q/3*0
Q = 330000*3*0
Q = 0
The heat of fusion for water is 3.3 x 105 J/kg. How much heat energy is needed to can 3kg of ice at 0°C to water at 0°C? Show your work.
Help please!! Don't give the answer, but please help me find the answer?! Thanks
2 answers
there is no temp change involved here, just the heat to melt at 0
Q = mass * heat of fusion
= 3 * 3.3*10^5
= 9.9 * 10^5 Joules
Q = mass * heat of fusion
= 3 * 3.3*10^5
= 9.9 * 10^5 Joules
1 answer