the half-life of radon-222 is 3.823 days. what was the original mass if 0.050g remains after 7.646 days?

Answer 1

k= 0.693/t_1/2
Then substitute k into the equation below.

ln(No/N) = kt
Solve for No.
N = 0.05g
k = from above.
t = 7.646 days.

Answer 2

The half-life of radon-222 is 3.823 days. What was the orginal mass if 0.050g reamains after 7.646 days? Show your work

Answer 3

236