every 10s the amount drops by 1/2, so
m(t) = 5 * 2^(-t/10)
The half-life of krypton-91 (91Kr) is 10 s. At time
t = 0
a heavy canister contains 5 g of this radioactive gas.
(a) Find a function
m(t) = m02−t/h
that models the amount of 91Kr remaining in the canister after t seconds.
1 answer
1 answer