If the physical half-life of sulfur-35 is 87.1 days, and the biologic half-life in the testicle is 632 days, what is its effective half-life in this organ?

I know i have to find the time and then the half-life.

But im having trouble finding the time

A(t)=Ao x e ^ (-0.693) (t) / T1/2 [half=life]

2 answers

I'm thinking to just divide 632 days by 87.1 days to determine the half-life
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