The ΔH of the reaction below is -575.13 kJ. Is this reaction spontaneous?

2ZnS + 3O2 + C → 2SO2 + 2Zn + CO2

A. It is not because the ΔH of the reaction is negative.
B. It is because the ΔH of the reaction is negative.
C. It depends on the temperature because the ΔH of the reaction is negative and the ΔS is negative.
D. It depends on the temperature because the ΔH of the reaction is negative and the ΔS is positive.

I believe the answer is a.

1 answer

Yes, this reaction is spontaneous. In a spontaneous reaction, the ΔH is negative, indicating that the reactants have a lower enthalpy than the products. The given reaction has a negative ΔH of -575.13 kJ, which means it is spontaneous.
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