since f' is decreasing, we know that f" < 0
So, at x=0, the slope is 0, and the curve is concave down, so it is a max there.
if f" is always negative, the curve is always concave down.
Looks like they're all true.
Consider the parabola y = -x^2
f' = -2x, which is always decreasing, and f'(0) = 0
f" = -2, and the parabola is always concave down.
So, only #1 is false.
The graph of f ′(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is false? (4 points)
The graph of f has an inflection point at x = 0.
The graph of f has a relative maximum at x = 0.
The graph of f is always concave down.
The graph of the second derivative is always negative.
I know that the first two are right, but not sure about the second two.
2 answers
The graph of f has an inflection point at x = 0. is the answer