Asked by joe9
The graph of f '(x) is continuous and decreasing with an x-intercept at x = -3. Which of the following statements must be true?
Answers
Answered by
MathMate
When f'(x) > 0, the function is increasing.
Conversely, f'(x) <0, function is decreasing.
Thus the function is increasing in the interval (-∞,-3], and decreasing on [-3,∞). This makes a maximum at x=-3.
Since we do not know anything about f"(x), we do not know about the concavity of the function.
Conversely, f'(x) <0, function is decreasing.
Thus the function is increasing in the interval (-∞,-3], and decreasing on [-3,∞). This makes a maximum at x=-3.
Since we do not know anything about f"(x), we do not know about the concavity of the function.
Answered by
Steve
all of them?
f is concave down with a max at x = -3
f is concave down with a max at x = -3
Answered by
jace
Since we are given f'(x) is a decreasing function, its derivative must be negative. Hence f ''(x) < 0, and f is concave down for all x.
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