At the x-axis, the y value is zero, so let y = 0
4x + 0 = 5
x = 5/4 , so point A is (5/4 , 0)
At the y-axis, the x value is zero, so let x = 0
0 + 2y = 5
y = 5/2 , so point B is (0 , 5/2)
slope = (5/2-0)/(0 - 5/4) = 2
other way:
if you have a linear equation of the form x/a + y/b = 1
then a is the x-intercept, and b is the y-intercept and the slope is b/a
4x+ 2y = 5
divide each term by 5
4x/5 + 2y/5 = 1
x/(5/4) + y/(5/2) = 1 , see the intercepts ?
slope = (5/2) / (5/4) = (5/2)(4/5) = 2
The graph of 4x + 2y= 5 cuts the x axis at point A and the y axis at point B. Find the:
Coordinates of point A.
Gradient of line A B.
2 answers
Draw the graph of the line represent by the equation
1 answer