A quadratic curve cuts the x-axis at 3 and -4.It cuts the y-axis at Z. The equation of the graph is y=ax^2+bx+c. Find ALL the posible values of a,b and c and the coordinates of Point Z.
4 answers
Coolguy -- be careful! You're stepping out of bounds.
Thanks Ms Sue For Repremanding Coolguy
You're welcome, Ackron.
y = k(x+4)(x-3)
now plug in x=0 to find z.
z = -12k
k = -z/12
So,
y = -z/12 (x^2+x-12)
= -z/12 x^2 - z/12 x + z
so, for each z there is only one possible value for each of a,b,c
now plug in x=0 to find z.
z = -12k
k = -z/12
So,
y = -z/12 (x^2+x-12)
= -z/12 x^2 - z/12 x + z
so, for each z there is only one possible value for each of a,b,c
0 answers