I don't know what you mean when you say: "The a axis scale set by a = 12 m/s^2."
That is not a sentence, and there is no "a axis".
t = 6s is 8 seconds after t = -2 s. If the acceleration rate is constant at 12 m/s^2, the velocity will increase by 8*12 = 96 m/s during that interval. That would make the new velocity 106 m/s.
The graph give the acceleration a versus time t for a particle moving along an x axis. The a axis scale set by a=12 m/s^2. At t = -2s the particle's velocity is 10 m/s. What is its velocity at t = 6s.
I know that I am supposed to used integrals to solve, but I can't figure it out. a(t) = -2x+8
If someone could show me the steps then I could find the answer.
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