d = 0.5a*t2^2 - 0.5a*t1^2
d = 0.5*0.5*4.4^2 - 0.5*0.5*1.2^2
d = 4.84 - 0.36 = 4.48 m.
The Graph above shows the speed of a car traveling in a straight line as a function of time. The car accelerates uniformly and reaches a speed Vb of 4.00 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 1.20 to 4.40 seconds.
1 answer