The glucose concentration of adults from Municipal X is normally distributed with mean of 75 mg/dL and standard deviation of 18 mg/dL. What is the proportion of the 30 households from Barangay Y with glucose concentration more than 105 mg/dL?

Question

Identify what is given: μ = _ σ = _ x = _

Using the same data from number 1, construct a 90% confidence interval for x.

Identify what is given:
n = __ σ = __ x = __ z-deviate = __
LL = __
UL = __

Answer 1

105 is 30 above the mean ... or 30/18 standard deviations

this is a z-score of 5/3 , or 1.667

use a z-score table to find the portion of the population above this score

Answer 2

how about the second one?

Answer 3

n = 30 σ = 18 x = 75 z-deviate = 1.6
LL = 69.5
UL = 80.4