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The gaseous hydrocarbon acetylene, C2H2, is used in welders' torches because of the large amount of heat released when acetylene burns with oxygen.

2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g)
How many grams of oxygen gas are needed for the complete combustion of 230. g of acetylene?
Answer in g.

1 answer

5 moles O2= 2 moles ace
2.5 moles O2=230g/molassAce
moles O2= 230/2.5 * 1/molmassAcd
gramsO2=32*molesO2=32*230/2.5 * 1/molmassAce
work out the molemass Ace, it ought to be 28+2 grams/mole
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