-2511.14 kJ/2 mols x 2 mols = ?
-2511.14 kJ/2 mols x 1 mol = ?
Oxyacetylene torches are fueled by the combustion of acetylene, C2H2.
2C2H2(g) + 5O2(g) --> 4 CO2(g) + 2H2O(g)
If the enthalpy change for the reaction is -2511.14 kJ/molrxn, how much heat can be produced by the reaction of
a. 2mol of C2H2?
b. 1 mol of C2H2?
c. .500 mol of C2H2?
d. .2000 mol of C2H2?
e. 10g of C2H2?
Can you help me set these up?
1 answer