The function h is defined by h(x)=x^(2)-x.
Find h(2x).
4 answers
(2x)^2-2x=4x^2-2x
Substitute 2x for x into the function, which would leave you:
h(x)=(2x)^2-2x
Factor out a 2x.
H(x)=2x(x-1) then set 2x and x-1 both equal to 0.
2x=0 x-1=0
x= 0 x=1
h(x)=(2x)^2-2x
Factor out a 2x.
H(x)=2x(x-1) then set 2x and x-1 both equal to 0.
2x=0 x-1=0
x= 0 x=1
My money is on bobpursley, big time!
Thanks I agree Reiny